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If 0.647 mil of oxygen are used in the burning of propane, how many moles of CO2 are produced

If 0647 mil of oxygen are used in the burning of propane how many moles of CO2 are produced class=

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drpelezo

Answer:

1.733 x 10⁻⁴ mole CO₂(g)

Explanation:

Assuming the rxn given is at STP conditions ...

                        C₃H₈             +       5O₂      =>             3CO₂    +    4H₂O

Given:             Excess             =  0.647ml                ?(moles)           -----  

                                          = 0.000647Liters

                                      = 6.47 X 10⁻⁴L/22.4L·mol⁻¹

                                        = 1.733 x 10⁻⁵ mol O₂

moles CO₂ = 3/5(2.89 x 10⁻⁴)mole CO₂ = 1.733 x 10⁻⁵ mole CO₂

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