Answer:
v₂ = 5.7 m/s
Explanation:
We will apply the law of conservation of momentum here:
[tex]Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\[/tex]
where,
Total Initial Momentum = 340 kg.m/s
m₁ = mass of bike
v₁ = final speed of bike = 0 m/s
m₂ = mass of Sheila = 60 kg
v₂ = final speed of Sheila = ?
Therefore,
[tex]340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\[/tex]
v₂ = 5.7 m/s
