The work of a student to solve a set of equations is shown: Equation A: y = 4 − 2z Equation B: 4y = 2 − 4z Step 1: −4(y) = −4(4 − 2z) [Equation A is multiplied by −4.] 4y = 2 − 4z [Equation B] Step 2: −4y = 4 − 2z [Equation A in Step 1 is simplified.] 4y = 2 − 4z [Equation B] Step 3: 0 = 6 − 6z [Equations in Step 2 are added.] Step 4: 6z = 6 Step 5: z = 1 In which step did the student first make an error? (5 points)​

Respuesta :

Answer:

The student made the first mistake in step 2.

Step-by-step explanation:

The work of a student to solve a set of equations first make an error in step 2 .

What is elimination method?

The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with multiplication or division of coefficients of the variables.

According to the question

Equation A: y = 4 − 2z

Equation B: 4y = 2 − 4z

Solving equation by elimination method

Step 1:

[Equation A is multiplied by −4.]

−4(y) = −4(4 − 2z)  

Equation B: 4y = 2 − 4z  

Step2:

[Equation A in Step 1 is simplified.]

-4y = -16 + 8z

Equation B: 4y = 2 − 4z

Step 3:

Both equation A and B is added

-4y = -16 + 8z

 4y = 2 − 4z  

=> 0 = -14 + 4z  

Step 4:

4z = 14

z = 3.5  

Hence, the work of a student to solve a set of equations first make an error in step 2 .

To know more about elimination method here:

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