Respuesta :

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Answer:

15.4 g

Explanation:

The reaction that takes place is:

  • 2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O

First we convert 5 grams of C₅H₁₀ into moles, using its molar mass:

  • 5 g ÷ 70 g/mol = 0.07 mol C₅H₁₀

Then we convert C₅H₁₀ moles into CO₂ moles, using the stoichiometric coefficients of the reaction:

  • 0.07 mol C₅H₁₀ * [tex]\frac{10molCO_2}{2molC_5H_{10}}[/tex] = 0.35 mol CO₂

Finally we convert 0.35 moles of CO₂ into grams:

  • 0.35 mol CO₂ * 44 g/mol = 15.4 g

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