Answer:
(x+11)² + (y-3)² = 121
Step-by-step explanation:
Let us assume we are given the following
Centre of a circle: (-11, 3)
Radius: 11
The standard equation of a circle is expressed as;
(x-a)² + (y-b)² = r²
(a, b) is the centre
r is the radius
a = -11, b = 3 and r = 11
Substitute
(x-(-11))² + (y-3)² = 11²
(x+11)² + (y-3)² = 121
Hence the required equation of the circle is (x+11)² + (y-3)² = 121
Note that the centre and the radius of the circle was assumed