Answer:
Step-by-step explanation:
Area of triangle with angle of 30°:
[tex]A_1=\frac12\cdot 5^2\cdot\sin(30^o)=\dfrac{25}4=6.25[/tex]
Area of triangle with angle of 50°:
[tex]A_2=\frac12\cdot 5^2\cdot\sin(50^o)=\dfrac{25}2\cdot0.766=9.575[/tex]
Area of the rest of the figure:
[tex]A_3=\dfrac{(360-30-50)^o}{360^o}\cdot\pi\cdot5^2=\dfrac79\cdot\pi\cdot25 =61.087[/tex]
Therefore:
[tex]A=A_1+A_2+A_3=6.25+9.575+61.087=76.912[/tex]