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what would be the final temperature of a mixture of water at 40 degree celsius temperature and 60 grams of water at 80 degree celsius temperature​

Respuesta :

Answer:

T = 60°C

Explanation:

We are given;

Mass of water in both cases as 60g.

Thus; m1 = m2 = 60 g

Temperature of first water; T1 = 40°C

Temperature of 2nd water; T2 = 80°C

Let final temperature be T.

To solve for the final temperature, we will use the formula;

(m1 + m2)T = ((m1•T1) + (m2•T2))

(60 + 60)T = ((60 × 40) + (60 × 80))

120T = 7200

T = 7200/120

T = 60°C

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