Rosy has 16 pencils and 24 erasers. She is putting together packets that will have an equal number of pencils and erasers in each packet. If Rosy uses all of the pencils and erasers, what is the maximum number of packets she can make?

i know this is late but the answer is 8 because your doing common factors so you you so 16 over 24 and see what number can go into both of those numbers which is 8 because 8 times 2=16 and 8 times 3= 24 so the answer is 8 again sorry i was late

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throwdolbeau throwdolbeau · Answer 2 · 2019-02-20T08:18:50+01:00

Answer:

Maximum number of packets made = 8

Step-by-step explanation:

Number of pencils Rosy has = 16

Number of erasers Rosy has = 24

Now, it is given all the packets made contain equal number of pencils and erasers in each packet.

Therefore, to find the maximum number of packets : We find the HCF of both 16 and 24

16 = 2 × 2 × 2 × 2

24 = 2 × 2 × 2 × 3

Common factors are : 2, 2 and 2

⇒ HCF = 2 × 2 × 2

= 8

So, 8 packets can be made from 16 pencils and 24 erasers so that each packet will contain 2 pencils and 3 erasers each.

Hence, Maximum number of packets made = 8