Answer: The new temperature is [tex]63^{o}C[/tex].
Explanation:
Given: [tex]V_{1}[/tex] = 1.90 L, [tex]T_{1} = 21.0^{o}C[/tex]
[tex]V_{2}[/tex] = 5.70 L, [tex]T_{2} = ?\\[/tex]
Formula used to calculate new temperature is as follows.
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{1.90 L}{21.0^{o}C} = \frac{5.70 L}{T_{2}}\\T_{2} = 63^{o}C[/tex]
Thus, we can conclude that the new temperature is [tex]63^{o}C[/tex].
