Step-by-step explanation:
Hey there!
Given;
a1 = 6
and r = 3
Then;
Let's see, we have a1 "first term" and r "common ratio". So, firstly use the formula.
[tex]nth \: term \: of \: geometric \: sries = {a}^{} . {r}^{n - 1} [/tex]
Now, keep all values.
[tex]nth = 6 \times {3}^{n - 1} [/tex]
So, it becomes like this.
Therefore, the rule is nth= 6*3^n-1.
Hope it helps!