A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block accelerate toward the end of the table where the mass was located. The student then places the block on the table and hangs a second, larger mass from the opposite end of the block. The block accelerates in the opposite direction from the first trial. What does this experiment demonstrate? Answer:

We know that acceleration can increase depending in the force applied on an object, any object with a greater mass will apply a greater force. F = M(a).

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moya1316 moya1316 · Answer 2 · 2021-09-16T14:51:56+02:00

This Newton's second law establishes a relationship between the summary of the external force and the acceleration of the body, It is demonstrated with the change in the direction and magnitude of the acceleration in the experiment

Newton's second law establishes a relationship between the net force and the acceleration, according to the expression

∑ F = m a

where ∑F is the sum of the external forces, m the mass and the acceleration of the body

In this case we have an initial situation, the block and a baking mass, therefore an acceleration is created towards the hanging mass given by

W₁ = M₁ g

F = ma

M₁ g = m a

a = [tex]\frac{M_1}{m} \ g[/tex]

where W₁ and M₁ are the weight and the masses of the mass of the body hanging under the acceleration of gravity.

In the second case, perhaps you have two masses, one on each side,

∑ F = W₁ -W₂

∑F = (M₁ -M₂) g

let's use Newton's second law

(M₁ -M₂ ) g = m a

a = [tex]\frac{M_1 - M_2}{m} \ g[/tex]

We can see that in the second case the acceleration depends on the difference of the hanging masses. This is a proof of Newton's second law where the effect on acceleration is due to the sum of all external forces and not of each force individually.

In conclusion with the realization of this experiment demostrate the valid true of Newton's second law

Learn more about Newton's second law here: https://brainly.com/question/19860811