Answer:
Correct option is
C
10
5
10P
5
Total ways in which one passenger can stop =10
Total ways in which 5 passengers can stop =10∗10∗10∗10∗10
=10
5
We will select 5 floors from 10 floors and assign each individual to each floor to keep everyone isolated from each other
No. of ways in which no two persons stop at the same floor =10C
5
∗5!
=10P
5
⇒P(E)=10P
5
/10
5
