Answer:
The mass of bromine liquid that participates in a chemical reaction=12.8 g
Explanation:
We are given that
Total number of moles of bromine liquid participate in chemical reaction=0.0800 moles
We have to find the mass of bromine liquid that participates.
Atomic mass of Br=79.9 g
1 mole of bromine liquid=2 atomic mass of bromine (Br)
1 mole of bromine liquid ([tex]Br_2[/tex]) =[tex]2\times 79.9=159.8 g[/tex]
0.0800 moles of bromine liquid=[tex]159.8\times 0.0800[/tex] g
0.0800 moles of bromine liquid=12.784 g
0.0800 moles of bromine liquid[tex]\approx 12.8[/tex] g
Hence, the mass of bromine liquid that participates in a chemical reaction=12.8 g
