Puppylover05
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Jason is pulling a box across the room. He is pulling with a force of 27 newtons and his arm is making a 49 angle with the horizontal, what is the horizontal component of the force he is pulling with?

Respuesta :

Force=27N

Angle=49

Vertical componenets:-

[tex]\\ \sf\longmapsto Fsin\theta[/tex]

[tex]\\ \sf\longmapsto 27sin49[/tex]

[tex]\\ \sf\longmapsto 27(0.7)[/tex]

[tex]\\ \sf\longmapsto 18.9N[/tex]

ferrybukantoro

Answer:

17.712 newtons

Step-by-step explanation:

the horizontal component of the force = Fh

Fh = F. cos 49°

= 27. (0.656)

= 17.712 newtons

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