Answer:
0= [tex]x^{2}[/tex]+3x
Step-by-step explanation:
Since y= x+1,
x+1=[tex]x^{2}[/tex]+4x+1
--> Bring x to the other side by changing sign.
1= [tex]x^{2}[/tex]+4x-x+1
1= [tex]x^{2}[/tex]+3x+1
--> Bring 1 to the other side by changing sign.
0= [tex]x^{2}[/tex]+3x+1-1
0= [tex]x^{2}[/tex]+3x+0
(Note: When there's is no number in the LHS side, it becomes 0)
--> Bring 0 on the RHS, to LHS
0-0= [tex]x^{2}[/tex]+3x
--> 0= [tex]x^{2}[/tex]+3x
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