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[correct answer gets 100 point + braininess]
Kiesha and her classmates wrote proportions for the reduction of a triangle.

A larger and smaller triangle have corresponding heights and bases.

Which proportions are set up correctly? Select three options.

StartFraction original height over original base EndFraction = StartFraction reduction

height over reduction base EndFraction
StartFraction original height over reduction height EndFraction = StartFraction original
base over reduction base EndFraction

StartFraction original height over reduction base EndFraction = StartFraction

reduction height over original base EndFraction

StartFraction reduction height over reduction base EndFraction = StartFraction

original height over original base EndFraction

StartFraction original height over original base EndFraction = StartFraction reduction

base over reduction height EndFraction

Question

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Respuesta :

Аноним Аноним · Answer 1 · 2021-10-01T07:43:54+02:00

[tex]\\ \sf\longmapsto \dfrac{Original\:Height}{Reduction\:height}=\dfrac{Original\:Base}{Reduction\:Base}\checkmark[/tex]

[tex]\\ \sf\longmapsto \dfrac{Reduction\:height}{Reduction\:Base}=\dfrac{Original\:Height}{Original\:Base}\checkmark[/tex]

[tex]\\ \sf\longmapsto \dfrac{Original\:Height}{Reduction\:Base}=\dfrac{Reduction\:Height}{Original\:Base}\checkmark[/tex]

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Аноним Аноним · Answer 2 · 2021-10-01T12:25:59+02:00

Answer:

[tex]{ \tt{{ \rm{ \frac{original \: height}{reduction \: base} = \frac{reduction \: height}{original \: base} }}

}} \\ [/tex]

[tex]{ \rm{ \frac{reduction \: height}{reduction \: base} = \frac{original \: height}{original \: base} }} \\ [/tex]

[tex]{ \rm{ \frac{original \: height}{original \: base} = \frac{reduction \: height}{reduction \: base} }} \\ [/tex]

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