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Marely walked around 2 rectangular parks. One measures 54 feet by 38 feet and the other measures 32 feet by 22 feet.
HOW FAR DID SHE WALK?

Marely's brother walked around a different park that is 48 feet by 33 feet
WHAT IS THE DIFFERENCE IN DISTANCE THAT MARLEY AND HER BROTHER WALKED?

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Tife14

Answer:

130 feet or 39.6m

Step-by-step explanation:

for Marely's first rectangular park, L=54 and B= 38

Total perimeter of distance walked in first rectangular park is 2(L+B), which is 2(54+38) =184 feet

For Marely's second rectangular park, L= 32 and B=22

Total perimeter of second distance 2(L+B), which is 2(32+22) = 108 feet

Total perimeter covered by Marely = (P1+P2) 184+108 = 292 feet

Marely's brother = 2(L+B)

2(48+33) = 162 feet

Hence, difference is 292-162 = 130 feet or 39.6m

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