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The width of a rectangle is ten more than three times its length. If its perimeter is 108 meters, find the rectangle's dimensions.

The width of a rectangle is ten more than three times its length If its perimeter is 108 meters find the rectangles dimensions class=

Respuesta :

Answer: the length is 3x+10

perimeter= 2 (width+length)

108=2(x+3x+10)

54=4x+10

4x=44

x=11(this is the width)

3x+10= 43(this is the length)

Step-by-step explanation:

Length be x

width be 3x+10

So

  • 2(3x+10+x)=108
  • 4x+10=54
  • 4x=44
  • x=11

width=3(10)+10=40m

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