Respuesta :
Ok say that x is the greatest number of 40 kg crates that can be loaded to the transport.
then 40x+82 must be at most 1050 kg because its the weight that the transport can handle
so that means algebraically
40x+82<= 1050
solve this inequality
40x+82-82<= 1050-82
40x<=968
40x/40 <= 968/40
x<= 24.2
so the greatest amount of 40 kg crates you can add is 24 crates
then 40x+82 must be at most 1050 kg because its the weight that the transport can handle
so that means algebraically
40x+82<= 1050
solve this inequality
40x+82-82<= 1050-82
40x<=968
40x/40 <= 968/40
x<= 24.2
so the greatest amount of 40 kg crates you can add is 24 crates
82+crates is less than or equal to 1050
crates=40 times number of crates (c)
82+40c≤1050
minus 82 both sides
40c≤968
divide both sides by 40
c≤24.2
round down since we can't put 0.2 crates on
24 crates is max number we can add
crates=40 times number of crates (c)
82+40c≤1050
minus 82 both sides
40c≤968
divide both sides by 40
c≤24.2
round down since we can't put 0.2 crates on
24 crates is max number we can add