Respuesta :
Following are the calculation to the voltage:
Given:
The voltage across a [tex]\bold{0.10 \mu \ F}[/tex] capacitor.
To find:
The function of the capacitor=?
Solution:
[tex]\to \bold{Q = CV}[/tex]
so,
[tex]\to \bold{I = \frac{dQ}{dt} = C\ \frac{dV}{dt}}[/tex]
As a result, this should nearly correspond to the gradient of the voltage curve.
from 0 to 1:
[tex]\to \frac{dV}{dt} = \frac{100}{1 \mu \ S}[/tex]
so [tex]I = 0.1 \times 100 = 10\ A[/tex]
from 1 to 2:
[tex]\to \frac{dV}{dt} = 0[/tex]
so [tex]I = 0[/tex]
from 2 to 4:
[tex]\to \frac{dV}{dt} = \frac{100}{2 \mu \ S}[/tex]
so [tex]I = 0.1 \times 50 = -5 A[/tex]
Therefore, the final answer is "third image".
Learn more:
brainly.com/question/14369084