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A hydraulic system is used to lift a 20,000 N vehicle in an auto garage. If the vehicle sits on
a piston with an area of 0.5 square meters, and a force is applied to a piston with an area
of 0.03 square meters, what is the minimum force that must be applied to lift the vehicle?

A hydraulic system is used to lift a 20000 N vehicle in an auto garage If the vehicle sits on a piston with an area of 05 square meters and a force is applied t class=

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satyamrana7c

Answer:

Explanation:

Area covered by the vehicle on the piston A1 = 0.5 m2  Weight of the vehicle, F1 = 2000 kg × 9.8 m s-2  Area on which force F2 is applied, A = 0.03 m2 P1 = P2 ;  F 1 A 1 F1A1 =  F 2 A 2 F2A2 and F2 = F 1 A 1 F1A1 A2 ;  F2 = (2000 × 9.8)  0.03 0.5 0.030.5 = 1176 NRead more on Sarthaks.com - https://www.sarthaks.com/957542/hydraulic-system-used-lift-2000-vehicle-in-an-auto-garage-if-the-vehicle-sits-on-piston-area

ck247730

Answer to the question is 1200n got it right on the test :)

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