clintonetti clintonetti

03-01-2017
Physics

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A child lifts a 5.0-newton toy to a height of 0.50 meters. How much work is done on the toy?

Respuesta :

naveenranjeet98 naveenranjeet98

03-01-2017

Work done=mgh
W=force*height
W=5N*0.50mts
W=2.5joule

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Аноним Аноним

03-01-2017

you can use the formula

Work = force x distance

therefore,

W= (5.0)(.50)
W = 2.5 joules

hope this helps :)

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