determine the force of gravitational attraction between a 4,000 kg elephant that is 10 meters away from a 180 kg lion

Respuesta :

Answer:

[tex]F_{g} = 4.8[/tex] × [tex]10^{-7}[/tex] [tex]N[/tex]

Explanation:

The law of gravitational attraction states :

[tex]F_{g} = G\frac{Mm}{R^{2} }[/tex]

G is the gravitational constant [tex](6.67[/tex] × [tex]10^{-11}[/tex][tex])[/tex]

M is the larger mass (kg)

m is the smaller mass (kg)

R is the distance separating the two objects ([tex]m^{2}[/tex])

∴ [tex]F_{g} =[/tex] [tex](6.67[/tex] × [tex]10^{-11}[/tex][tex])[/tex]  [tex](4000)(180)/(10)^{2}[/tex]

[tex]F_{g} = 4.8[/tex] × [tex]10^{-7}[/tex] [tex]N[/tex] is the gravitational force between the elephant and the lion.