Mr. Jones wants to add a cement path around his new pool. The pool has a radius of 7 feet. The cement path will be 1 foot wide and
go all the way around the pool. What is the square footage of the path?

Respuesta :

The square footage of the path is 47.1 ft²

The area of a circle is:

A = πr²

Where r is the radius of the circle.

Let us assume that the pool is a circle.

Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.

Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.

The square footage of the path =  πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²

Hence The square footage of the path is 47.1 ft²

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