An equation of the line that contains the origin and the point (1, 2) is
a) y = 2x
b) 2y = x
c) y = x - 1 d) y = 2x + 1 e) =x-1
d) y = 2x + 1 e) =x-1
e) =x-1

We can plug in the two points of (1, 2) and (0, 0) to find our answer. I am going to start by plugging in (0, 0). If it works, I will then plugin (1, 2)

a) y = 2x

0 = 2(0)

0 = 0 ✓

2 = (2)1

2 = 2 ✓

-> We got lucky, the first equation satisfies the question!

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

An equation of the line that contains the origin and the point (1, 2) is a) y = 2x b) 2y = x c) y = x - 1 d) y = 2x + 1 e) =x-1 d) y = 2x + 1 e) =x-1 e) =x-1

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An equation of the line that contains the origin and the point (1, 2) is
a) y = 2x
b) 2y = x
c) y = x - 1 d) y = 2x + 1 e) =x-1
d) y = 2x + 1 e) =x-1
e) =x-1