Based on the given data, the amount of products from 5.00 g of KClO₃ is:
- 0.04 moles of KCl
- 2.98 g KCl
- 2.41 * 10²² molecules of KCl
- 0.06 moles of O₂.
- 1.92 g of O₂
- 3.61 * 10²² molecules of O₂
What amount of products is formed from the decomposition of KClO₃?
The decomposition of KClO₃ is given by the equation below:
2 KClO₃ -----> 2 KCl + 3 O₂
2 moles of KClO₃ produces 2 moles of KCl and 3 moles of O₂
Molar mass of KClO₃ is 122.5 g/mol
molar mass of KCl = 74.5 g
molar mass of O₂ = 32 g
Moles of KClO₃ in 5.00 g = 5.00/122.5
- moles of KClO₃ = 0.04 moles
For KCl
a. moles: 0.04 moles of KClO₃ will produce 0.04 moles of KCl
b. mass of KCl = 0.04 * 74.5 = 2.98 g KCl
c. number of molecules of KCl = 0.04 * 6.02 * 10²³ = 2.41 * 10²² molecules of KCl
For O₂:
a. moles of O₂; 0.04 moles of KClO₃ will produce = 0.06 moles of O₂.
b. mass of O₂ = 0.06 * 32 g = 1.92 g of O₂
c. number of molecules: 0.06 * 6.02 * 10²³ = 3.61 * 10²² molecules of O₂
Therefore, the amount of products from 5.00 g of KClO₃ is:
- 0.04 moles of KCl
- 2.98 g KCl
- 2.41 * 10²² molecules of KCl
- 0.06 moles of O₂.
- 1.92 g of O₂
- 3.61 * 10²² molecules of O₂
Learn more about moles and molecules at: https://brainly.com/question/26135244
