If ABCD is dilated by a factor of 2, the
coordinate of D' would be:
5
4
3
С
2.
B.
-8
-7
-6
-5
-4
-3
-2
-1 0
1
2
3
4
5
6
7
8
9
10
11
-1
A
-2
D
-3
D' = ([?], [ ]
=
Enter
Assuming the dilation is centered at the origin, you can simply double the coordinates. This gives you [tex]D'(3 \times 2, -2 \times 2) = (6, -4)[/tex]
