Hello.
The first step is to subtract 14 from both sides:
[tex]\mathrm{33-14 > \frac{v}{3} +14-14}[/tex]
[tex]\mathrm{33-14 > \frac{v}{3} }[/tex]
[tex]\mathrm{19 > \frac{v}{3} }[/tex]
Now, multiply both sides by 3 in order to get rid of the fraction:
[tex]\mathrm{19*3 > \frac{v}{3} *3}[/tex]
[tex]\mathrm{57 > v}[/tex]
Since 57 is greater than v, v is less than 57:
[tex]\mathrm{v < 57}[/tex]
Therefore, your answer is
[tex]\mathrm{v < 57}[/tex]
I hope this helps.
Have a nice day.
[tex]\boxed{imperturbability}[/tex]
