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7. Rust is iron (III) oxide (Fe2O3). The owner of a 1959 Cadillac convertible wants to
restore it by removing the rust with oxalic acid, but he needs to know how many
moles of rust will be involved in the reaction. How many moles of iron (III) oxide
are contained in 2.50 kg of rust?

Respuesta :

asuwafohjames

The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.

What is a mole?

A mole is the mass of a substance that contains 6.023×10²³ particles of that substance.

To calculate the number of moles of iron (III) Oxide contained in 2.5 kg of the rust, we use the formula below.

Formula:

  • n = R.m/m.m................. Equation 1

Where:

  • n = number of mole of iron (III) oxide
  • R.m = mass of iron (III) oxide that is involved in the reaction (rusting)
  • m.m = molar mass of iron (III) oxide.

From the question,

Given:

  • R.m = 2.5 kg = 2500 g
  • m.m of Fe₂O₃ = [(2×56)+(3×16)] = (112+48) = 160 g/mol

Substitute these values into equation 1

  • n = 2500/160
  • n = 15.625 moles.

Hence, The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.

Learn more about moles here: https://brainly.com/question/15356425

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