What is the equation of a circle with center (−5, −8) and radius 2?

(x − 5)2 + (y − 8)2 = 4

(x + 5)2 + (y + 8)2 = 4

(x + 5)2 + (y + 8)2 = 2

(x − 5)2 + (y − 8)2 = 2

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DᴀʀᴋPᴀʀᴀᴅᴏx DᴀʀᴋPᴀʀᴀᴅᴏx · Answer 1 · 2022-04-03T05:21:13+02:00

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Standard equation of circle ~

[tex]\qquad \sf \dashrightarrow \:(x - h) {}^{2} + (y - k) {}^{2} = r {}^{2} [/tex]

where,

Now, let's plug in the values ~

[tex]\qquad \sf \dashrightarrow \:(x - (5)) {}^{2} + (y - ( - 8)) {}^{2} = {2}^{2} [/tex]

[tex]\qquad \sf \dashrightarrow \:(x + 5) {}^{2} + (y + 8) {}^{2} = {4}^{} [/tex]

Therefore, the correct choice is B

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MrRoyal MrRoyal · Answer 2 · 2022-05-04T10:43:10+02:00

The equation of the circle with a center of (4,5) and a radius of 2 units is (x + 5)² +(y + 8)² = 4

The center of the circle is given as:

Center (a,b) = (-5, -8)

The radius is given as:

Radius, r = 2

The equation of the circle is calculated using:

(x - a)² + (y - b)² = r²

Substitute values for r and (a,b)

(x + 5)² +(y + 8)² = 2²

Evaluate the square of 2

(x + 5)² +(y + 8)² = 4

Hence, the equation of the circle is (x + 5)² +(y + 8)² = 4

Read more about circle equations at:

https://brainly.com/question/1559324

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