The amount of money which is expected to lose if the game of spinner is played 1000 times is $111.
Probability of an event is the ratio of number of favorable outcome to the total number of outcome of that event.
You spin the spinner two times.
Let suppose there are total 12 outcomes on a spinner which has 12 blocks. In this block, 4 is blue. The probability of getting blue twice in this spinner and earning $15 is,
[tex]P=\dfrac{4}{12}\times\dfrac{4}{12}\\P=\dfrac{1}{9}[/tex]
The probability of not getting two blue in two spun and losing $2 is,
[tex]P^{-1}=1-\dfrac{1}{9}\\P^{-1}=\dfrac{8}{9}[/tex]
The money to expect to win or lose if you play this is,
[tex]E(X)=15\times\dfrac{1}{9}-2\times\dfrac{8}{9}\\E(X)=-0.111[/tex]
For 1000 games,
[tex]E(X)=-0.111\times1000\\E(X)=-111[/tex]
Thus, the amount of money which is expected to lose if the game of spinner is played 1000 times is $111.
Learn more about the probability here;
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