given:
per min= 24 cubic ft
radius= 4 ft
to find:
how fast the surface rises.
solution:
[tex]area = \pi {r}^{2} [/tex]
[tex]a = \pi \times {4}^{2} [/tex]
[tex]a = 50.24 \: {ft}^{2} [/tex]
[tex]v = 24 \: {ft}^{3} [/tex]
[tex] = \frac{24}{50.24} [/tex]
[tex] = 0.48[/tex]
therefore, the rising in the surface area is 0.48 feet per minute.
