When an aqueous solution of KBr is electrolyzed,
the following process occurs.
KBr + H2O → KOH + Br2 + H2
Balance this equation and indicate the sum of
the coefficients of all of the species
1. four
2. twelve
3. eight
4. two
(No one seems to be answering me anymore lol)

KBr + H2O = KOH + Br2 + H2

So we know that we need a 2 on the left of kbr so it would equal the right Br.

=2KBr
now put a 2 in front of KOH since we need a 2k on right side

Now we put a 2 infront of H2O which wil make 4 h's and 2 o's

2h2o

now it is balanced

2KBr + 2H2O = 2KOH + Br2 + H2

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When an aqueous solution of KBr is electrolyzed, the following process occurs. KBr + H2O → KOH + Br2 + H2 Balance this equation and indicate the sum of the coefficients of all of the species 1. four 2. twelve 3. eight 4. two (No one seems to be answering me anymore lol)

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When an aqueous solution of KBr is electrolyzed,
the following process occurs.
KBr + H2O → KOH + Br2 + H2
Balance this equation and indicate the sum of
the coefficients of all of the species
1. four
2. twelve
3. eight
4. two
(No one seems to be answering me anymore lol)