For part A, we will see that the distance is 7 units. For part B, the distance from Nina's house to the school to the grocery store is larger.
Remember that the distance between two points (a, b) and (c, d) is:
[tex]D = \sqrt{(a - c)^2 + (b - d)^2}[/tex]
A) Her house is at (-4, 10), and her school is at (-4, 3), so the distance is:
[tex]D = \sqrt{(-4 - (-4))^2 + (10 - 3)^2} = \sqrt{7^2} = 7[/tex]
The distance is 7 units.
B) In the first case, the distance between the school and the grocery store is:
[tex]D' = \sqrt{(-4 - (-4))^2 + (3 - (-6))^2} = 9[/tex]
So the total distance is 9 + 7 = 16
And the distance between the school and the community center is:
[tex]D'' = \sqrt{(-4 - 2)^2 + (3 - 3)^2} = 6[/tex]
So the total distance is 6 + 7 = 13
So we can see that the total distance from Nina's house, to the school, to the grocery store is larger than the other.
If you want to learn more about distance:
https://brainly.com/question/23848540
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