The statement "They are parallel and congruent" is true for the line segments.
Given that, triangle ABC is translated using the rule (x, y) → (x + 1, y − 4) to create triangle A′B′C′.
In mathematics, a translation is an up, down, left, or right movement of a shape. Because the translated shapes appear to be exactly the same size as the original ones, they are consistent with one another.
Now, let us consider coordinates as [tex]A(2,3)[/tex] and [tex]B(-4, 6)[/tex].
By using rule (x, y) → (x + 1, y − 4), we get [tex]A'[/tex] as (2+1, 3-4)=(3, -1) and [tex]B'[/tex] as (-4+1, 6-4)=(-3, 2).
Now, using the distance formula, [tex]Distance=\sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }[/tex] we have to calculate the distance of AA' and BB'.
That is, [tex]AA'=\sqrt{(3-2)^{2} +(-1-3)^{2} } =\sqrt{17}[/tex] units.
[tex]BB'=\sqrt{(-3-(-4))^{2}+(2-6)^{2} }= \sqrt{17}[/tex].
Since the length of AA' and BB' are the same they congruent.
Therefore, the statement "They are parallel and congruent" is true for the line segments.
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