Answer:
[tex]c=4 \sqrt{2}[/tex]
Step-by-step explanation:
Pythagoras Theorem
[tex]a^2+b^2=c^2[/tex]
where:
Given values:
Substitute the given values into Pythagoras Theorem formula and solve for c:
[tex]\begin{aligned}a^2+b^2 & = c^2 \\\implies 4^2+4^2 & =c^2\\16+16 & =c^2\\32 & =c^2\\ \sqrt{c^2}& =\sqrt{32}\\ c & =\sqrt{16 \cdot 2}\\& = \sqrt{16}\sqrt{2}\\& =4\sqrt{2}\end{aligned}[/tex]
Therefore, the measure of the third side of the given right triangle is [tex]4 \sqrt{2}[/tex]
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