The vertical asymptote of f(x) is (A) x = 0, –9.
To find the vertical asymptote of f(x):
The vertical asymptotes of a function are the zeroes of the denominator of a rational function
The function is given as: [tex]f(x) = \frac{(x-9)}{(x^{3} -81x)}[/tex]
Set the denominator to 0:
Factor out x:
Express 81 as 9^2:
Express the difference between the two squares:
Split, [tex]x=0[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].
Solve for x:
Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.
(See attachment for the graph of f(x))
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The complete question is given below:
Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).
A) x = 0, –9
B) x = –9
C) x = 0, 9
D) x = 9