The area of the two similar triangles are in the ratio 16 : 25.
As given in the question,
Let the similar triangles be ABC , EFG.
Sides of triangles ABC , EFG. are in the ratio are AB:EF =8:10
As per the theorem,
Area of two similar triangles is equal to square of the ratio of the corresponding sides
Area of ΔABC / Area of ΔEFG = AB² / EF²
= 8² / 10²
= 16 /25
Therefore, the area of the two similar triangles are in the ratio 16 : 25.
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