It takes the car 13.2 seconds to stop
The car travels 19.2 m while stopping
Explanation:The coefficient of kinetic friction, μ = 0.224
The initial velocity, u = 28.9 m/s
The final velocity, v = 0 m/s
The force acting in the x-direction is:
[tex]\begin{gathered} \sum ^{}_{}f=ma_x \\ \mu_kmg=ma_x \\ 0.224m(9.8)=ma_x \\ a_x=0.224(9.8) \\ a_x=2.1952m/s^2 \end{gathered}[/tex]The time taken for the car to stop can be calculated using the formula:
[tex]\begin{gathered} v=u+a_xt \\ 0=28.9-2.1952t \\ t=\frac{28.9}{2.1952} \\ t=13.2\text{ seconds} \end{gathered}[/tex]The distance travelled
[tex]\begin{gathered} S=ut+\frac{1}{2}at^2 \\ S=28.9(13.2)+0.5(-2.1952)(13.2^2) \\ S=190.2m \end{gathered}[/tex]