SOLUTION
[tex](x+6)^2+(y+8)^2=9[/tex]Recall that the equation of circle is given as;
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ where \\ (a,b)\text{ is the centre} \\ r\text{ is the radius.} \end{gathered}[/tex]Considering our question;
[tex]\begin{gathered} (x-(-6))^2+(y-(-8))^2=3^2 \\ \Rightarrow r=3 \end{gathered}[/tex]The radius of the circle is 3 units