[tex]estimated\text{ }y-\text{intercept = 94.510}[/tex]
Explanation:[tex]\begin{gathered} \text{Linear regression formula:} \\ ŷ=b_0+b_1x \\ \text{where b}_0\text{ = y-intercept} \\ b_1\text{ = slope} \end{gathered}[/tex]
[tex]\begin{gathered} \text{The linear regression gotten from earlier solution using the values in the table was:} \\ ŷ=-7.09223x+94.50971 \end{gathered}[/tex]
We'll obtain the intercept from equation we got earlier:
[tex]\begin{gathered} \text{comparing both the equation:} \\ ŷ=-7.09223x+94.50971 \\ ŷ=b_0+b_1x \\ ŷ=b_1x\text{ + }b_0 \\ ŷ=ŷ \\ -7.09223x\text{ = }b_1x \\ b_0\text{ =}94.50971 \\ b_1\text{ = }-7.09223 \end{gathered}[/tex]
From the above,
[tex]\begin{gathered} b_0\text{ = y-intercept = }94.50971 \\ \\ \text{Estimated }y-\text{intercept to thr}ee\text{ decimal place = 94.510} \end{gathered}[/tex]
