We need to estimate the amount of string that Oliver and Destiny have.
We know Oliver has 5 pieces of string that are each 4 2/12 feet long. We can write it, in feet, as:
[tex]5\cdot(4\frac{2}{12})=5\cdot(4+\frac{2}{12})=5\cdot4+5\cdot\frac{2}{12}=20+\frac{10}{12}[/tex]Now, we can estimate the value 10/12 by rounding the numerator and the denominator, each, to the nearest ten:
[tex]\frac{10}{12}\cong\frac{10}{10}=1[/tex]Thus, Oliver is estimated to have 21 feet of string.
Now, Destiny has 4 pieces of string that are each 5 14/16 feet long. We can write it, in feet, as:
[tex]4\cdot(5\frac{14}{16})=4\cdot(5+\frac{14}{16})=4\cdot5+4\cdot\frac{14}{16}=20+\frac{56}{16}[/tex]Then, we can estimate the value 56/16 by rounding the numerator and the denominator, each, to the nearest ten:
[tex]\frac{56}{16}\cong\frac{60}{20}=3[/tex]Thus, Destiny is estimated to have 23 feet of string.
Notice that:
[tex]23>21[/tex]Therefore, Destiny is estimated to have more feet of string.
