Given the equation:
[tex]C=8.50+0.16U[/tex]Where:
C is the cost of shipping a package
U is the number of ounces.
Given:
Average number of ounces = 21
Standard deviation = 5.5
Let's find the mean and standard deviation of the cost.
To find the mean of the cost, substitute the mean of the ounces for U and evaluate.
Substitute 21 for U:
[tex]\begin{gathered} C=8.50+0.16(21) \\ \\ C=8.50+3.36 \\ \\ C=11.86 \end{gathered}[/tex]Therefore, the mean of the cost is $11.86
To find the standard deviation of the cost, substitute the standard deviation of the ounces for U and evaluate.
Substitute 5.5 for U:
[tex]\begin{gathered} C=8.50+0.16(5.5) \\ \\ C=8.50+0.88 \\ \\ C=9.38 \end{gathered}[/tex]The standard deviation of the cost is $9.38.
ANSWER:
• Mean of the cost = 11.86
,• Standard deviation of the cost = 9.38
