ANSWER
1.09 · 10⁶ Pa
EXPLANATION
The pressure of a fluid of density ρ, at a depth h is:
[tex]p=\rho\cdot h\cdot g[/tex]Where g is the acceleration of gravity.
In this problem we have h = 111 m, the fluid is water so its density is ρ = 1000 kg/m³ and we can use for the gravity g = 9.8 m/s². The pressure at the foot of the dam is:
[tex]\begin{gathered} p=1000\frac{kg}{m^3}\cdot111m\cdot9.8\frac{m}{s^2} \\ p=1087800\cdot\frac{kg}{m\cdot s^2}=1087800Pa \end{gathered}[/tex]We can rewrite this in scientific notation for better undestanding:
[tex]p=1.09\cdot10^6\text{ Pa}[/tex]