Determine the molarity of a solution formed by dissolving 0.589 g of Mgl2 in enough water to yield 75.0 mL of solution.A. 0.0946 Mb. 0.0337 Mc. 0.0282 Md. 0.0107 Me. 0.0589 m

Respuesta :

Explanation:

Molarity is the ratio between the amount of substance in the solute, measured in mol (n1), and the volume of the solution in liters (V). This concentration is measured in mol per liter (mol/L).

The mathematical formula used to calculate this concentration is given by:

M = n1/V

First, we need to transform 0.589 g of MgI2 into moles. For this, we use the molar mass of MgI2.

Molar mass of Mg = 24.305 g/mol

molar mass of I = 126.90 g/mol

MgI2 = (1*24.305) + (2*126.90) = 278.1 g/mol

Now we use the following formula to transform grams to moles: moles = mass/molar mass

mass = 0.589 g

molar mass = 278.1 g/mol

moles = 0.589/278.1

moles = 2.1 x 10^-3

Now let's calculate the molarity:

n1 = 2.1 x 10^-3 moles

V = 75 mL = 0.075 L

M = 2.1 x 10^-3 /0.075

M = 0.0282 M

Answer: Alternative c. 0.0282 M