SOLUTION
From the question, we can make another sketch:
From this sketch, we can see that it is a right triangle problem that can be
solve using the Pythagoras theorem
[tex]\begin{gathered} \text{hypotenuse}^2=adjacent^2+opposite^2 \\ \text{From the sketch above } \\ \text{hypotenuse side = 14ft} \\ \text{adjacent side =11ft} \\ \text{opposite side = x } \end{gathered}[/tex][tex]\begin{gathered} \text{hypotenuse}^2=adjacent^2+opposite^2 \\ 14^2=11^2+x^2 \\ 14^2-11^2=x^2 \\ 196-121=x^2 \end{gathered}[/tex][tex]\begin{gathered} 75=x^2 \\ \sqrt[]{75}=\sqrt[]{x^2} \\ 8.660ft\text{ =x} \\ \text{8}.7ft(to\text{ 1 decimal place)=x} \end{gathered}[/tex]The correct option is C