We are given a question about factory plants making TV panels. The following information holds.
Plant A produces twice as many panels as plant B. This can be expressed mathematically as:
[tex]A=2B[/tex]Also, 2% and 3% of the TV panels from Plant A and Plant B are defective, and both plants produced a total of 490 defective panels. This can be expressed mathematically as:
[tex]\frac{2A}{100}+\frac{3B}{100}=490[/tex]We can clearly see that we have derived two equations. We will substitute the first equation in the second equation to get the number of panels Plant B produced.
[tex]\begin{gathered} \frac{2(2B)}{100}+\frac{3B}{100}=490 \\ \frac{4B}{100}+\frac{3B}{100}=490 \\ \frac{7B}{100}=490 \\ \text{Cross multiply} \\ 7b=490\times100 \\ B=\frac{490\times100}{7} \\ B=70\times100 \\ B=7000 \end{gathered}[/tex]Therefore, the number of panels that plant B produced is:
ANSWER: 7000
