Respuesta :
We need to find the points at which the expression below intercept the axis of the coordinate plane:
[tex]2x+\frac{2}{3}y=-2[/tex]To find the "x" intercept we need to find the value of "x" that results in a value of "y" equal to 0. We have:
[tex]\begin{gathered} 2x+\frac{2}{3}\cdot0=-2 \\ 2x+0=-2 \\ 2x=-2 \\ x=\frac{-2}{2}=-1 \end{gathered}[/tex]To find the "y" intercept we need to find which value of "y" the function outputs when we make x equal to 0.
[tex]\begin{gathered} 2\cdot0+\frac{2}{3}y=-2 \\ \frac{2}{3}y=-2 \\ 2y=-6 \\ y=\frac{-6}{2}=-3 \end{gathered}[/tex]The x intercept is -1 and the y intercept is -3.
