Given function:
[tex]f(x)=xe^x[/tex]The minimum value of the function can be found by setting the first derivative of the function to zero.
[tex]f^{\prime}(x)=xe^x+e^x[/tex][tex]\begin{gathered} xe^x+e^x\text{ = 0} \\ e^x(x\text{ + 1) = 0} \end{gathered}[/tex]Solving for x:
[tex]\begin{gathered} x\text{ + 1 = 0} \\ x\text{ = -1} \end{gathered}[/tex][tex]\begin{gathered} e^x\text{ = 0} \\ \text{Does not exist} \end{gathered}[/tex]Substituting the value of x into the original function:
[tex]\begin{gathered} f(x=1)=-1\times e^{^{-1}}_{} \\ =\text{ -}0.368 \end{gathered}[/tex]Hence, the minimum value in the given range is (-1, -0.368)
