SOLUTION
Step 1 : Attached is the graph that shows the solutions of the two equations:
Step 2: We need the get the values of x and y in the two sets of the equations.
[tex]\begin{gathered} x\text{ + 2y }\leq\text{ 500 --equ 1 multiplied by 3 = 3 x + 6y }\leq\text{ 1500 ---equ 3} \\ 3x\text{ + 4y }\leq\text{ 1200 ---- equ 2} \\ \text{equ 3 minus equ 2, we have that :} \\ 6y\text{ - 4y }\leq\text{ }1500\text{ - 1200} \\ 2y\text{ }\leq\text{ 300} \\ \text{Divide both sides by 2 , we have that:} \\ y\text{ }\leq150 \\ \text{put y }\leq\text{ 150 in equ 1, } \\ x\text{ + 2y }\leq\text{ 500} \\ x\text{ + 2 (150 ) }\leq\text{ 500} \\ x\text{ + 300 }\leq\text{ 150} \\ x\text{ }\leq\text{ 500 - 300} \\ x\text{ }\leq\text{ 200} \end{gathered}[/tex]
CONCLUSION: It means that the number of shirts, x = 200
while the number of pyjamas , y = 150
